A gas 'X' is dissolved in water at 2 bar pressure. Its mole fraction is 0.02 in solution. The mole fraction water when the pressure of gas is doubled at the same temperature is :

Options

A. 0.04
B. 0.98
C. 0.96
D. 0.02

Answer

C

Explanation

`p=K_(H)x`
`2=K_(H)xx0.02`...(i) ltgtbrgt `4=K_(H)xxx`....(ii)
From eqs. (i) and (ii),
`(1)/(2)=(0.02)/(x)`
`x=0.04`
Mole fraction of water `= 1- 0.04 = 0.96`]