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The expression relating mole fraction of...

The expression relating mole fraction of solute `(x_(2))` and molarity (M) of the solution is :
(where `rho` is the density of solution and `M_(1) and M_(2)` are the molar masses of solvent and solute, respectively.)

A

`x_(2)=(MM_(1))/(M(M_(1)-M_(2))+rho)`

B

`x_(2)=(MM_(1))/(M(M_(1)-M_(2))-rho)`

C

`x_(2)=(M(M_(1)-M_(2))+rho)/(MM_(1))`

D

`x_(2)=(M(M_(1)-M_(2))-rho)/(MM_(1))`

Text Solution

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The correct Answer is:
A
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