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A solution of sucrose (molar mass = 342 ...

A solution of sucrose (molar mass `= 342 "g mol"^(-1)`) has been prepared by dissolving 68.5g of sucrose in 1000g of water. The freezing point of the solution obtained will be :
(`K_(f)` for water `= 1.86 "K kg mol"^(-1)`)

A

`-0.372^(@)C`

B

`-0.520^(@)C`

C

`+0.372^(@)C`

D

`-0.570^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaT=K_(f)xx(w_(B)xx1000)/(m_(B)xxw_(A))`
`=1.86xx(68.5xx1000)/(342xx1000)`
`=0.372`
Freezing point of solution `= - 0.372^(@)C`
`=- 0.372^(@)C`]
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