A solution of `CaCl_(2)` was prepared by dissolving 0.0112g in 1 kg of distilled water (molar mass of `Ca = 41 g mol^(-1)` and `Cl =35.5 g mol^(-1)`). The freezing point constant of water is `2 "K kg mol"^(-1)`. The depression in the freezing point of the solution is :

Options

A. 0.0002
B. 0.002
C. 0.003
D. 0.0006

Answer

D

Explanation

van't Hoff factor of `CaCl_(2)` will be 3
`:. DeltaT=ixxK_(f)xx(w_(B)xx1000)/(m_(B)xxw_(A))`
`=3xx2xx(0.0112xx1000)/(112xx1000)=6xx10^(-4)`]