The mole fraction of a given sample of I...

The mole fraction of a given sample of `I_(2) " in " C_(6)H_(6) " is " 0.2`. The molality of `I_(2) " in " C_(6) H_(6)` is:

`0.32`

`3.2`

`0.032`

`0.48`

Text Solution

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The correct Answer is:

`m = (x_(B) xx 1000)/((1 - x_(B))m_(A)) " " m =` molality
`m = (0.2 xx 1000)/(0.8 xx 78) " " x_(B) =` mole fraction of solution `m_(A) =` molar mass of solvent

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