Home
Class 11
PHYSICS
A bolt of mass 0.2 kg falls from the cei...

A bolt of mass 0.2 kg falls from the ceiling of an elevator moving down with a uniform speed of `5 m s^(-1)`. It hits the floor of the elevator (length of the elevator = 5 m) and does not rebound. The amount of heat produced by the impact is (Take `g = 10 m s^(-2)`)

A

5 J

B

10 J

C

15 J

D

20 J

Text Solution

Verified by Experts

The correct Answer is:
B
Here, m=0.2 kg, `v= 5 m s^(-1)`
h = length of elevator = 5 m
As relative velocity of the bolt w.r.t. elevator is zero, therefore, in the impact, only potential energy of the bolt is converted into heat energy.
Amount of heat produced = Potential energy lost by the ball = mgh
`=(0.2 kg) (10 m s^(-2)) (5 m) =10 J`
Promotional Banner

Topper's Solved these Questions

  • WORK , ENERGY AND POWER

    NCERT FINGERTIPS|Exercise The Conservation Of Mechanical Energy|12 Videos

  • WORK , ENERGY AND POWER

    NCERT FINGERTIPS|Exercise The Potential Energy Of A Spring|6 Videos

  • WORK , ENERGY AND POWER

    NCERT FINGERTIPS|Exercise The Work Energy Theorem For A Variable Force|3 Videos

  • WAVES

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

A bob of mass 0.3 kg falls from the ceiling of an elevator moving down with a uniform speed of 7ms^(-1) . If hits the floor of the elevator (length of the elevator = 3m) and does not rebound. What is the heat produced by the impact ? Would your answer be different if the elevator were stationary ?

A block of mass 2 kg rests on the floor of an elevator , which is moving down with an acceleration 'g' , then the apparent weight of the block is [ take g = 10 m//s^(2) ]

An elevator car whose floor to ceiling distance is equal to 2.7m starts ascending with constant acceleration 1.2 m//s^2. 2 s after the start, a bolt begins falling from the ceiling of the car. Find (a)the time after which bolt hits the floor of the elevator. (b)the net displacement and distance travelled by the bolt, with respect to earth. (Take g=9.8 m//s^2)

A man (mass =50 kg) is in an elevtor with is moving with acceleration 0.49 m//s^(2) upwards. Find normal reaction exerted by man on floor of the elevator.

An elevator without a ceiling is ascending with a constant speed of 10 m//s. A boy on the elevator shoots a ball directly upward, from a height of 2.0 m above the elevator floor. At this time the elevator floor is 28 m above the ground. The initial speed of the ball with respect to the elevator is 20 m//s. (Take g=9.8m//s^2 ) (a) What maximum height above the ground does the ball reach? (b) How long does the ball take to return to the elevator floor?

A rubber ball dropped from a height of 20m (g=10m/s^(2)) falls on the roof of an elevator going up at 2m/s. If the collision of the ball with the elevator is elastic, the ball rebounds with a velocity of?

A rubber ball dropped from a height of 20m (g=10m/s^(2)) falls on the roof of an elevator going up at 2m/s .If the collision of the ball with the elevator is elastic, the ball rebounds with a velocity of

An elevator without a ceiling is ascending up with an acceleration of 5 ms^-2. A boy on the elevator shoots a ball in vertical upward direction from a height of 2 m above the floor of elevator. At this instant the elevator is moving up with a velocity of 10 ms^-1 and floor of the elevator is at a height of 50 m from the ground. The initial speed of the ball is 15 ms^-1 with respect to the elevator. Consider the duration for which the ball strikes the floor of elevator in answering following questions. ( g=10 ms^-2 ) 1. The time in which the ball strikes the floor of elevator is given by

A man of mass 75 kg is standing in an elevator which is moving with an acceleration of 5 m//s^2 in upward direction.The apparent weight of the man will be (g=10 m//s^2)