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A current of 2.0A passed for 5 hours thr...

A current of 2.0A passed for 5 hours through a molten metal salt deposits 22.2 g of metal (At. Wt. =177). The oxidation state of the metal in the metal salt is

A

`+1`

B

`+2`

C

`+3`

D

`+4`

Text Solution

Verified by Experts

The correct Answer is:
C
Let oxidation state of metal in its salt is +n
`M^(n+)=0.94V +ne^(-)rarrM`
` t= 5 "hours" =5xx60xx60s,I=2.0A`.
`Q=1 xxt=2xx5xx60xx60C=36000C`
To deposit 177g of M electricity required
`=nxx96500C`
To deposit 22.2g of M electricity required
`n=(nxx96500xx22.2)/(177)`
`( nxx96500xx22.2)/(177)=36000`
`n=(36000 xx177)/(96500xx22.2)=2.97=3`
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