Equal volumes of `0.1M AgNO_(3)` and `0.2M NaCI` are mixed. The concentration of `NO_(3)^(-)` ions in the mixture will be

Options

A. `0.1M`
B. `0.05M`
C. `0.2M`
D. `0.15M`

Answer

B

Explanation

`underset(0.1M)(AgNO_(3))+underset(0.2M)(NaCI) rarr AgCI +NaNO_(3)`
`0.1M AgNO_(3)` reacts with `0.1M NaCI` to produce `0.1M AgCI` and `0.1M NaNO_(3)`
`:. NO_(3)^(-) = (0.1M)/(2) = 0.05M`
`[ :'` When equal volumes are mixed dilution occurs]