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If 5.85g of NaClare dissolved in90g of w...

If `5.85`g of `NaCl`are dissolved in`90g` of water,the moles fraction of`NaCl` is

A

`0.1`

B

`0.01`

C

`0.2`

D

`0.0196`

Text Solution

Verified by Experts

The correct Answer is:
D
Mole fraction of `NaCI`
`= (5.85//58.5)/((90)/(18)+(5.85)/(58.5)) = (0.1)/(5.1) = 0.0196`
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