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0.15g of a substance dissolved in 15g of...

0.15g of a substance dissolved in 15g of a solvent boiled at a temp. higher by `0.216^(@)C` than that of the pure solvent. Find out the molecular weight of the substance `(K_(b)` for solvent is `2.16^(@)C`)

A

1.01

B

10.1

C

100

D

10

Text Solution

Verified by Experts

The correct Answer is:
C
`M = (K_(b).W_(b).1000)/(DeltaT_(b).W_(A))`
`=(2.16 xx 0.15 xx 1000)/(216 xx 15) = 100`
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