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An aqueous solution freezes at -0.186^...

An aqueous solution freezes at
`-0.186^(@)C (K_(f)=1.86^(@)` ,`K_(b)=0.512^(@))`. What is the elevation in boiling point?

A

`0.186`

B

`0.512`

C

`(0.512)/(1.86)`

D

`0.0512`

Text Solution

Verified by Experts

The correct Answer is:
D

`DeltaT_(f) = k_(f) xx m` or `m = (Delta T_(f))/(k_(f)) = (0.186)/(1.86) = 0.1`
`:. DeltaT_(b) = k_(b) xx m = 0.512 xx 0.1 = 0.0512^(@)`
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