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1.8 g of fructose (C(6)H(12)O(6)) is add...

`1.8` g of fructose `(C_(6)H_(12)O_(6))` is added to `2` kg of water. The freezing point of the solution is

A

`-1.86^(@)C`

B

`0.186^(@)C`

C

`-0.0186^(@)C`

D

`-0.0093^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaT_(f) = K_(f) xx m = 1.86 xx (1.8)/(180) xx (1)/(2)`
`= 1.86 xx (1)/(200) = 0.0093^(@)`
It is to be below `0^(@)C :. DeltaT_(f) =- 0.0093^(@)C`
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