A 1% aqueous solution (M/V) of a certain substance is isotonic with a 3% solution of glucose (M. mass 180). The molar mass of the substance is

Options

A. 60
B. 120
C. 180
D. 360

Answer

A

Explanation

For isotonic solutions
`(n_(1))/(V_(1)) = (n_(2))/(V_(2))`
`(m_(1))/(M_(1)xx V_(1)) = (m_(2))/(M_(2)xx V_(2))`
`(1)/(M_(1)xx100) = (3)/(180 xx 100)`
`M_(1) = 60`