The volume of water to be added to `100 cm^(3)` of `0.5 NH_(2)SO_(4)` to get decinormal concentration is

Options

A. `400 cm^(3)`
B. `500 cm^(3)`
C. `450 cm^(3)`
D. `100 cm^(3)`

Answer

A

Explanation

`N_(1)V_(1) = N_(2)V_(2)`
`0.5 N xx 100 cm^(3) = 0.1 N xx V_(1)`
`V_(1) = 500 cm^(3)`
Water to be added `= (500 - 100) cm^(3) = 400 cm^(3)`