The volume of water to be added to `N//2 HCI` to prepare `500 cm^(3)` of `N//10` solution is

Options

A. `45cm^(3)`
B. `400 cm^(3)`
C. `450cm^(3)`
D. `100cm^(3)`

Answer

B

Explanation

`N_(1)V_(1) = N_(2)V_(2)`
`(N)/(2) xx V_(1) = (N)/(10) xx 500`
`V_(1) = 100`
Vol of `N//10` solution `= 500 cm^(3)`
Vol. of `N//2` solution `= 100 cm^(3)`
`:.` Water to be added `= (500 - 100) cm^(3) = 400 cm^(3)`