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3.65grams of HCI dissolved in 16.2g of w...

3.65grams of HCI dissolved in 16.2g of water. The mole fraction of HCI in the resulting solution is

A

0.4

B

0.3

C

0.2

D

0.1

Text Solution

Verified by Experts

The correct Answer is:
D
`n(HCI) = (3.65)/(36.5) = 0.1mol`
`n(H_(2)O) = (16.2)/(18) = 0.9` mol
`X (HCI) = (n(HCI))/(n(HCI)+n(H_(2)O))`
`= (0.1)/(0.1+0.9) = 0.1`
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