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Relative lowering in vapour pressure of ...

Relative lowering in vapour pressure of solution containing non-volatile solute is directly proportional to mole fraction of solute. Above statement is

A

Henry law

B

Dulong and Petit law

C

Raoult's law

D

Le-Chatelier's principle

Text Solution

Verified by Experts

The correct Answer is:
C

According to Raoult's law, V.P. of a solution containing a non-volatile solute, B.
`P_(s)=x_(A)xxP^(@)`
where, `x_(A)` = mole fraction of solvent, `P^(@)` = V.P. of pure solvent
`P_(s)=(1-x_(B))P^(@)`
where `x_(B)` = mole fraction of solute
`(P^(@)-P_(B))/(P^(@))=x_(B)`
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Knowledge Check

  • Vapour pressure of the solution of a non- volatile solute is always __.

    A
    equal to the vapour pressure of pure solvent
    B
    higher than vapour pressure of pure solvent
    C
    lower than vapour pressure of pure solvent
    D
    constant
  • The relative lowering of vapour pressure of an aqueous solution containing non-volatile solute is 0.0125. The molaliry of the solution is

    A
    `0.70`
    B
    `0.50`
    C
    `0.60`
    D
    `0.80`
  • The relative lowering of vapour pressure of an aqueous solution containing non-volatile solute is 0.0125. The molality of the solution is

    A
    0.7
    B
    0.5
    C
    0.6
    D
    0.8
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