The average osomotic pressure of human blood is 7.8 bar at `37^(@)C`. What is the concentration of an aqueous `NaCI` solution that could be used in the blood stream?

Options

A. `0.16 mol//L`
B. `0.32 mol//L`
C. `0.60mol//L`
D. `0.45 mol//L`

Answer

A

Explanation

`pi=7.8" bar ", T = 37^(@)C = 300 K`
`R = 0.083L " bar " mol^(-1)K^(-1)`
i = 2 for `Na^(+) Cl^(-)`
`pi = (I xx n_(B)xx R xx T)/(V)`
`(n_(B))/(V)= (pi)/(iRT)`
`=(7.8"bar")/(2xx(0.083 L^(-1)mol^(-1)K^(-1))xx300K)`
`= 0.1566 mol L^(-) = 0.16 mol/L`