Two solutions of a substance (non-electrolyte) are mixed in the following manner. `480 mL` of `1.5M` first solution `+520 mL` of `1.2M` second solution. What is the molarity of the final mixture?

Options

A. `1.20M`
B. `1.50M`
C. `1.344 M`
D. `2.70M`

Answer

C

Explanation

`underset(("1st sol"))(M_(1)V_(1)) + underset(("2nd sol"))(M_(2)V_(2)) = underset(("Mixture"))(M_(3)V_(3))`
`1.5xx480+1.2xx520=M_(3)(480+520)`
`1.5xx480+1.2xx520=M_(3)(480+520)`
`1000 M_(3) = 720+ 624`
`M_(3) = (1344)/(1000)=1.344 M`