Equal volumes of ethylene glycol (molar mass = 62) and water (molar mass = 18) are mixed. The depression in freezing point of water is (given `K_(f)` of water `= 1.86 K mol^(-1)` kg and specific gravity of ethylene glycol is 1.11)

Options

A. `0.0033`
B. 3.33
C. `0.333`
D. `33.3`

Explanation

To solve the problem, we need to calculate the depression in the freezing point of water when equal volumes of ethylene glycol and water are mixed. Here’s a step-by-step solution:

### Step 1: Understand the Given Data
- Molar mass of ethylene glycol (C2H6O2) = 62 g/mol
- Molar mass of water (H2O) = 18 g/mol
- Freezing point depression constant (Kf) of water = 1.86 K kg/mol
- Specific gravity of ethylene glycol = 1.11

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