The vapour pressure of water at `23^(@)C` is 19.8 mm of Hg 0.1 mol of glucose is dissolved in `178.2g` of water. What is the vapour pressure (in mm Hg) of the resultant solution?

Options

A. `19.0`
B. `19.602`
C. `19.402`
D. `19.202`

Answer

B

Explanation

n(glucose) = 0.1
n(water) `= (178.2)/(18) = 9.9`
x(water) `=(9.9)/(9.9+0.1)=0.99`
p(solution) `= p^(@)` (solvent) `xx` x(solvent)
`= (19.8 mm Hg)xx 0.99`
`= 19.602 mm Hg`