`2N HCI` solution will have the same molar concentration as a

Options

A. `4.0 N H_(2)SO_(4)`
B. `0.5 NH_(2)SO_(4)`
C. `1N H_(2)SO_(4)`
D. `2N H_(2)SO_(4)`

Answer

A

Explanation

`2N HCl=2g eq L^(-1)=2 mol L^(-1)` [Eqn. mass = Mol mass]
`4N H_(2)SO_(4)=4g eq L^(-1) = 4xx49 g L^(-1)`
`=4xx(49)/(98)=2 mol L^(-1)`
(Eq. mass of `H_(2)SO_(4)=49` , Mol mass = 98)