Molality of an aqueous solution that produce an elevation of boiling point of 1.00 K at 1 atm pressure. `K_(b)` for water is `0.512 K kg mol^(-1)`

Options

A. `0.512m`
B. `0.195m`
C. `1.95m`
D. `5.12m`

Answer

C

Explanation

`Delta T_(b)=K_(b)xxm`
`therefore m=(Delta T_(b))/(K_(b))=(1)/(0.512)=1.953 m`