Home
Class 12
CHEMISTRY
The vapour pressure of a pure liquid is ...

The vapour pressure of a pure liquid is 0.80 atm. When a non-volatile solute is added to this liquid, its vapour pressure drops to 0.60 atm. The mole fraction of the solute in the solution is

A

0.75

B

0.2

C

0.25

D

0.85

Text Solution

Verified by Experts

The correct Answer is:
C
`(p^(@)-p_(s))/(p^(@)) = x_("solute")`
`:. x_("solute") = (80-60)/(80) = (1)/(4) = 0.25`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    DINESH PUBLICATION|Exercise OBJECTIVE TYPE MCQs|47 Videos

  • SOLUTIONS

    DINESH PUBLICATION|Exercise Paragraph 1|1 Videos

  • SOLUTIONS

    DINESH PUBLICATION|Exercise ULTIMATE PREPARATORY PACKAGE|10 Videos

  • SOLID STATE

    DINESH PUBLICATION|Exercise Brain storming|10 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    DINESH PUBLICATION|Exercise ULTIMATE PREPARATORY PACKAGE|20 Videos

Similar Questions

Explore conceptually related problems

The vapour pressure of pure liquid solvent 0.50 atm. When a non-volatile solute B is added to the solvent, its vapour pressure drops to 0.30 atm. Thus, mole fraction of the component B is

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of pure liquid is 1.2 atm. When a non-volatile substance B is mixed in A, then its vapour pressure becomes 0.6 atm. The mole fraction of B in the solution is

The vapour pressure of pure liquid solvent A is 0.80 atm.When a non volatile substances B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the components B in the solution is:

Why vapour pressure of a liquid decreases when a non - volatile solute is added to it ?

The vapour pressure of pure liquid A is 0.80 atm. On mixing a non-volatile B to A, its vapour pressure becomes 0.6 atm. The mole fraction of B in the solution is:

DINESH PUBLICATION-SOLUTIONS -REVISION QUESTION
  1. A real solution is that which:

    Text Solution

    |

  2. The vapour pressure of a dilute aqueous solution of glucose is 740 mm ...

    Text Solution

    |

  3. The vapour pressure of a pure liquid is 0.80 atm. When a non-volatile ...

    Text Solution

    |

  4. 36 g of glucose (molar mass = 180 g//mol) is present in 500 g of water...

    Text Solution

    |

  5. For getting accurate value of molar mass of a solute by osmotic pressu...

    Text Solution

    |

  6. For a dilute solution, Raoult's law states that

    Text Solution

    |

  7. 200 mL of an aqueous solution of a protein contains its 1.26g. The osm...

    Text Solution

    |

  8. The empirical formula of a non-electrolyte is CH(2)O. A solution conta...

    Text Solution

    |

  9. A solution containing 1.8 g of a compound (empirical formula CH(2)O) ...

    Text Solution

    |

  10. Ethylene glycol is used as an antifreeze in a cold cliamate Mass of et...

    Text Solution

    |

  11. The degree of dissociation (alpha) of a weak electrolyte, A(x)B(y) is ...

    Text Solution

    |

  12. A 5.2 molal aqueous of methyl alcohol, CH(3)OH, is supplied. What is t...

    Text Solution

    |

  13. Dissolving 120g of urea (mol wt 60) in 100 g of water gave solution of...

    Text Solution

    |

  14. The freezing point (in .^(@)C) of a solution containing 0.1g of K(3)[F...

    Text Solution

    |

  15. The freezing point depression constant for water is -1.86^(@)Cm^(-1).i...

    Text Solution

    |

  16. Mole fraction of a solution in 1.00 molal aqueous solution is

    Text Solution

    |

  17. The system that forms maximum boiling azeotrope is

    Text Solution

    |

  18. The van't Hoff factor i for a compound which undergoes dissociation in...

    Text Solution

    |

  19. A 0.1 molal aqueous solution of a weak acid is 30% ionized. If K(f) fo...

    Text Solution

    |

  20. A solution containing 1.8 g of a compound (empirical formula CH(2)O) ...

    Text Solution

    |