`36` g of glucose (molar mass `= 180 g//mol)` is present in `500` g of water, the molarity of the solution is

Options

A. 0.2
B. `0.4`
C. 0.8
D. `1`

Explanation

To find the molarity of a solution containing 36 g of glucose in 500 g of water, we can follow these steps:

### Step 1: Calculate the number of moles of glucose
To find the number of moles of glucose, we use the formula:

\[ \text{Number of moles} = \frac{\text{mass of solute (g)}}{\text{molar mass of solute (g/mol)}} \]

Given:
- Mass of glucose = 36 g
- Molar mass of glucose = 180 g/mol

\[ \text{Number of moles of glucose} = \frac{36 \, \text{g}}{180 \, \text{g/mol}} = 0.2 \, \text{mol} \]

### Step 2: Calculate the volume of the solution in liters
Since we are given the mass of water, we can find the volume of the solution. The density of water is approximately 1 g/mL, so:

\[ \text{Volume of water (mL)} = \text{mass of water (g)} = 500 \, \text{g} \]

To convert this to liters:

\[ \text{Volume of water (L)} = \frac{500 \, \text{g}}{1000 \, \text{g/L}} = 0.5 \, \text{L} \]

### Step 3: Calculate the molarity of the solution
Molarity (M) is defined as the number of moles of solute per liter of solution:

\[ \text{Molarity (M)} = \frac{\text{Number of moles of solute}}{\text{Volume of solution (L)}} \]

Substituting the values we calculated:

\[ \text{Molarity} = \frac{0.2 \, \text{mol}}{0.5 \, \text{L}} = 0.4 \, \text{mol/L} \]

### Final Answer
The molarity of the solution is **0.4 mol/L**.

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