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Osmotic pressure of a solution is 0.0821...

Osmotic pressure of a solution is `0.0821 atm` at a temperature of 300 K. The concentration in mole/litre will be

A

`0.33`

B

`0.066`

C

`0.3 xx 10^(-2)`

D

3

Text Solution

Verified by Experts

The correct Answer is:
C
`pi=CRT or C = pi//RT`
`C=(0.0821atm)/((0.0821"L atm K"^(-1) mol^(-1))xx300K)`
`=0.3xx10^(-2)mol L^(-1)`
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