The density (in g `mL^(-1))` of a `3.60M` sulphuric acid solution that is `29% H_(2)SO_(4)` (Molar mass `= 98 g mol^(-1))` by mass will be

Options

A. `1.45`
B. `1.04`
C. `1.88`
D. `1.22`

Answer

D

Explanation

29% `H_(2)SO_(4)` by mass means 29g `H_(2)SO_(4)` are present in 100g of the solution
If `"d g mL"^(-1)` is the density of the solution,
Volume `= (100)/(d) mL = (1)/(10 d)L`
Moles of `H_(2)SO_(4) =(29)/(98)` mole
Molarity `= (29//98 "mol")/(1//10 d)`
`3.60 = (29 xx 10 d)/(98)`
`d = (3.60)/(10) xx (98)/(29) = 1.22 "g mL"^(-1)`.