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The ionisation energy of gaseous Na atom...

The ionisation energy of gaseous Na atoms is `495.8 KJ mol^(-1)`. The lowest possible frequency of light that can ionise a Na atom is

A

`1.24xx10^(15) s^(-1)`

B

`4.76 xx 10^(14) s^(-1)`

C

`1.24xx10^(12) s^(-1)`

D

`3.15 xx 10^(14) s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
E=hv or v=`E/h`
`=(495.8xx10^(3) "J/atom")/(6.02xx10^(23))xx(1)/(6.62xx10^(-34)Js)`
`=1.24xx10^(14)s^(-1)`
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