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The electronegativity difference between...

The electronegativity difference between two atoms A and B is `2`, then percentage of covalent character in the molecule is

A

`54%`

B

`46%`

C

`23%`

D

`72%`

Text Solution

Verified by Experts

The correct Answer is:
A
The percentage ionic character ionic character is related to electronegativity difference between the two atoms. It is given by Hanny and Smith relationship.
% age ionic character. =16`(X_A-X_B)+3.5(X_A-X_B)^2`
Here, `X_A and X_B` are electronegativities of two atoms A and B
`therefore` % ionic character =16(2)+`3.5(2)^2`=46%
or covalent character = 100-46 =54%
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