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The bond angle in H2O (for H-S-H) is...

The bond angle in `H_2O` (for H-S-H) is

A

same as that of Cl-Be-Cl in `BeCl_2`

B

greater than H-N-H bond angle in `NH_3`

C

greater than H-Se-H and less than H-O-H

D

same as Cl-Sn-Cl in `SnCl_2`

Text Solution

Verified by Experts

The correct Answer is:
C

The bond angle in `BeCl_2=180^@` , in `NH_3=107^@`, in `H_2O=104.5^@`, in `SnCl_2=119^@`
whereas that of
is close to `90^@`
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