Home
Class 11
CHEMISTRY
The number of mole of oxalate ions oxidi...

The number of mole of oxalate ions oxidised by one mole of `MnO_(4)^(-)` ion is:

Text Solution

Verified by Experts

The redox reaction is :
`2MnO_(4)^(-)+16H^(+)+5C_(2)O_(4)^(2-)rarr2Mn^(2+)+10CO_(2)+8H_(2)O`
2 moles of `MnO_(4)^(-)` oxidise `C_(2)O_(4)^(2-)` ions =5mole
1 mole of `MnO_(4)` oxidises `C_(2)O_(4)^(-)` ions =`5//2` mol
Since `x/y`=`5/2`, Therefore" x=5,y=2. or x+y=7
Promotional Banner

Topper's Solved these Questions

  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Value Based Question|2 Videos

  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise (Oxidation & Reduction) very short answer questions (Assingnment)|12 Videos

  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Additional Important Question|31 Videos

  • RATES OF REACTIONS AND CHEMICAL KINETICS

    DINESH PUBLICATION|Exercise Ultimate Preparatory Package|29 Videos

  • S-BLOCK ELEMENTS (ALKALI AND ALKALINE EARTH METALS )

    DINESH PUBLICATION|Exercise Assertion reason|12 Videos

Similar Questions

Explore conceptually related problems

The number of mole of oxalate ions oxidised by one mole of MnO_(4)^(-) is :

The number of moles of oxalate ions oxidised by one mole of MnO_(4)^(-) ion in acidic medium is :

The number of moles of ferrus oxalate oxidised by one mole of KMnO_(4) in acidic medium is:

The number of Fe^(2+) ion oxidised by one mole of MnO_(4)^(-) ions is:

1 mole of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium, Hence value of x is:

10 moles of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium. The value of 'x' is :

Calculate the number of moles of Sn^(2+) ion oxidise by 1 mole of K_(2)Cr_(2)O_(7) in acidic medium.

What is the number of coulombs required for the conversion of one mole of MnO_(4)^(-) to one mole of Mn^(2+) ?

Five moles of ferric oxalate are oxidise by how much mole of KMnO_(4) in acidic medium.