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Write the cell reaction that occurs when...

Write the cell reaction that occurs when the following half-cells are combined.
`I_(2)+2e^(-)to 2l^(-)(IM) , " "E^(@)=0.54 V`
`Br_(2)+2e^(-)to 2Br^(-)(IM) , " "E^(@)=1.08 V`

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Verified by Experts

The half cell reaction with lesser `E^(@)` value takes place at the anode while the other takes place at the cathode. Thus
`{:("At anode: " 2I^(-) to I_(2)+2e^(-) " (oxidation)"),("At cathode : " Br_(2)+2e^(-) to 2Br^(-) " (reduction )"),("cell reaction: " bar(" "2I^(-) +Br_(2)to I_(2) +2Br^(-))):}`
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Write the cell reaction that occurs when the folowing half cells are combined. I_(2)+2e^(-)rarr2I^(-)(1M), E^(@)=+0.54 V Br_(2)+2e^(-)rarrBr^(-)(1M),e^(@)=+1.08 V

Which of the following is the cell reaction that occurs when the following half-cells are combined? I_2 + 2e^(-) to 2I^(-) (1M) , E^@=+0.54 V Br_2+2e^(-) to 2Br (1 M) , E^@=+1.09 V

I2 and Br2 are added to a solution containing Br– and I– ions. What reaction will occur if, I_(2) + 2e^(-) rarr 2I^(-) , E^(0) = + 0.54V and Br_(2) + 2e^(-) rarr 2Br^(-) , E^(0) = +1.09 V?

The standard reduction potential for the half-cell reaction, Cl_2 + 2e^(-) to 2Cl^(-) will be (Pt^(2+)+2Cl^(-)to Pt + Cl_2 , E_"cell"^@=-0.15 V , Pt^(2+) + 2e^(-) to Pt, E^@=1.20 V)

Consider the following half cell reactions : Br_(2) + 2e^(-) to 2 Br^(-) " " E^(@) = 1.09 V I_(2) + 2e^(-) to 2 I^(-) " " E^(@) = 0.54 V If I_(2) and Br_(2) are added to solution containing 1 M concentration of I^- and Br^- respectively . How will the increase in the concentration of Br^(-) affect E_(cell) ?

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