A zinc rod is dipped in 0.1 M `ZnSO_(4)` solution. The salt is 95% dissociated of this dilution at 298 K. Calculate electrode potential.
`(E_(Zn^(2+)//Zn)=-0.76 V)`.

Explanation

To calculate the electrode potential of a zinc rod dipped in a 0.1 M ZnSO₄ solution that is 95% dissociated at 298 K, we can follow these steps:

### Step 1: Determine the concentration of Zn²⁺ ions
The dissociation of ZnSO₄ can be represented as:
\[ \text{ZnSO}_4 \rightarrow \text{Zn}^{2+} + \text{SO}_4^{2-} \]

Given that the salt is 95% dissociated, we can calculate the concentration of Zn²⁺ ions:
- Initial concentration of ZnSO₄ = 0.1 M
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