A voltaic cell is set up at `25^(@)C` with following half cells : `Ag^(+)(0.001 M)|Ag` and `Cu^(2+)(0.10 M)|Cu` What would be the voltage of this cell ? `(E_(cell)^(@)=0.45 V)`

Explanation

To find the voltage of the voltaic cell set up with the given half-cells, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Half-Reactions**:
- For the silver half-cell:
\[
\text{Ag}^+ + e^- \rightarrow \text{Ag} \quad (E^\circ = +0.80 \, \text{V})
...