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Calculate equilibrium constant for the r...

Calculate equilibrium constant for the reaction at `25^(@)C`
`Cu(s)+2Ag^(+)(aq) hArr Cu^(2+)(aq)+2Ag(s)`
`E^(@)` value of the cell is 0.46`" V "`.

Text Solution

Verified by Experts

`E_(cell)`=0.46 V, n=2
`log K_(c)=(nE_(cell)^(@))/(0.0591)=(2xx0.46)/(0.0591)=15.6`
`K_(c)="Antilog " 15.6=3.98xx10^(15)`.
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