How many coulombs are required for the reduction of 1 mol of `MnO_(4)^(-) " to " Mn^(2+)`?

Explanation

To determine how many coulombs are required for the reduction of 1 mole of \( \text{MnO}_4^{-} \) to \( \text{Mn}^{2+} \), we can follow these steps:

### Step 1: Write the half-reaction
The reduction of permanganate ion \( \text{MnO}_4^{-} \) to manganese ion \( \text{Mn}^{2+} \) can be represented as:
\[ \text{MnO}_4^{-} + \text{H}^{+} + \text{e}^{-} \rightarrow \text{Mn}^{2+} + \text{H}_2\text{O} \]

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