An acidic solution of `Cu^(2+)` ions containing 0.4 g of `Cu^(2+)` ions is electrolysed until all the copper is deposited. Calculate the valume of oxygen evolved at N.T.P.

Explanation

The redox reaction taking place in solution is :
`H_(2)O(l)rarr 2H^(+)(aq)+1//2 O_(2)(g)+2e^(-) " "("oxidation")`
`Cu^(2+)(aq)+2e^(-)rarr Cu(s) " "("reduction")`
`{:(Cu^(2+)(aq)+H_(2)O(l)rarrCu(s)+2H^(+)(aq)+1//2 O_(2)(g)),(63.5//2=31.75 g " "1//2xx22400 cc=11200 "cc"):}`
31.75 g of `Cu^(2+)` ions evolve oxygen gas at N.T.P.=11200 cc
0.4 g of `Cu^(2+)` ions evolve oxygen gas at N.T.P. `=((11200 "cc"))/((31.75 g))xx(0.4g)=141 " cc"`