How many coulombs are required to produce 50.0 g of aluminium from molten `Al_(2)O_(3)` ?

Explanation

To determine how many coulombs are required to produce 50.0 g of aluminum from molten \( \text{Al}_2\text{O}_3 \), we will follow these steps:

### Step 1: Write the balanced chemical equation
The reduction of aluminum oxide \( \text{Al}_2\text{O}_3 \) to aluminum can be represented as:
\[ \text{Al}_2\text{O}_3 + 6e^- \rightarrow 2\text{Al} + 1.5\text{O}_2 \]
This equation shows that 6 moles of electrons are required to produce 2 moles of aluminum.
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