The measured resistance of a conductivity cell containing `7.5xx10^(-3)` M solution of KCl at `43^(@)` C was 1005 ohms. Calculate (a) Specific conductance (b) Molar conductance of the solution. Given cell constant =1.25 `cm^(-1)`.

Explanation

To solve the problem, we will calculate the specific conductance and molar conductance of the given KCl solution step by step.

### Given Data:
- Molarity of KCl solution (C) = \(7.5 \times 10^{-3} \, \text{M}\)
- Resistance (R) = \(1005 \, \Omega\)
- Cell constant (L/A) = \(1.25 \, \text{cm}^{-1}\)

### Step 1: Calculate Specific Conductance (K)
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