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The electrical resistance of a column of...

The electrical resistance of a column of `0.05 " mol " L^(-1)` NaOH solution of diameter 1 cm and length 50 cm is `5.55xx10^(3)" ohm "`.Calculate its resistivity,conductivity and molar conductivity.

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To solve the problem step by step, we will calculate the resistivity, conductivity, and molar conductivity of the given NaOH solution. ### Step 1: Calculate the Area of Cross-Section Given: - Diameter of the solution column, \( d = 1 \, \text{cm} \) - Radius, \( r = \frac{d}{2} = \frac{1}{2} = 0.5 \, \text{cm} \) The area \( A \) of the cross-section can be calculated using the formula: ...
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Calculating resistivity, conductivity and motor conductivity : The electrical resistance of a column of 0.05 mol L^(-1) NaOH solution of diameter 1 cm and length 50 cm is 55 xx 10^(3) ohm . Calculate its resistivity, conductivity and molar conductivity Strategy: Assuming the column of solution to be cylindrical determine the area of cross-section, A . Using it along with the length of column, calculate resistivity. Reciprocal of resistivity yields conductivity. When we divide conductivity by molar concentration, we get molar conductivity.

The electrical resistance of a column of 0.05 M N aOH solution of diameter 1 cm and length 50 cm is 5.55 xx 10^(3)ohm . Calculate its resistivity , conductivity, and molar conductivity.

The electrical resistance of a column of 0.04M NaOH solution of diameter 1.2 cm and length 50cm is 5.55xx10^(3)ohm , the resistivity of the column would be

The questions consist of two atatements each, printed as Assertion and Reason. While answering these questions you are required to choose any one of the following four responses : The electrical resistance of a column of 0.5 M NaOH solution of diameter 1 cm and length 50 cm is 5.55 xx 10^3 "ohm" . Its resistivity is equal to 75.234 Omega cm .

The resistance of 0.05 M NaOH solution is 31.6 Omega and its cell constant is 0.357 cm^(-1) . Calculate its conductivity and molar conductivity .

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