The resistance of a conductivity cell contaning `0.001M KCl` solution at `298K` is `1500Omega`. What is the cell constant if conductivity of `0.001M KCl` solution at `298K` is `0.146 xx 10^(-3)S cm^(-3) S cm^(-1)`.

Explanation

Resistance (R )=1500`Omega`
`"Conductance" (C )=(1)/(R )=(1)/(1500" ohm")=(1)/(1500)S`
`"Conductivity" (k)=0.146xx10^(-3)" S "cm^(-1)`
`"Cell constant"(l//a)=("Conductivity")/("Contance") =((0.146xx10^(-3)" S "cm^(-1)))/((1//1500" S"))=0.219 cm^(-1)`