How much Charge is required for the following reductions `:`
`a. 1 mol of Al^(3+) to Al`
`b.` ` 1 mol of Cu^(2+) to Cu`
`c.` `1 mol of MnO_(4)^(-)` to `Mn^(2+)?`

Explanation

(i) `" " Al^(3+)(aq)+underset(3" Faraday")(3e^(-))toAl(s)`
`"Charge" =3xxF=3xx96500" C"= 2.895xx10^(5)C`
(ii) `" " Cu^(2+)(aq)+ underset(2 " Faraday")(2e^(-))toCu(s)`
`"Charge"=2xxF=2xx96500" C "=1.93xx10^(5) C`.
(iii) `" " underset(O.N. of Mn=+7)(MnO_(4)^(-))+5e^(-) to underset(O.N. of Mn=+2)(Mn^(2+))`
`"Charge"=5xxF=5xx96500" C"=4.825xx10^(5)" C"`.