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In the electrolysis of a solution contai...

In the electrolysis of a solution containing `H^(+)` and `Cu^(2+)` ions, at the cathode `H^(+)` ions are liberated in preference to `Cu^(2+)` ions. Is the statement correct ?

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Verified by Experts

No, it is wrong, `Cu^(2+)` ions are discharged in preference to `H^(+)` ions because `E^(@)` value of `Cu^(2+)//Cu` is more than that of `2H^(+)//H_(2)`.
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