Predict the products of electrolysis of a solution of `H_(2)SO_(4)` using platinum electrodes.

Explanation

(a) By the elctrolysis of dilute solution of `H_(2)SO_(4)`
For answer, consult 18(N.C.E.R.T. Exercise).
(b) By the electrolysis of strong `H_(2)SO_(4)`
`H_(2)SO_(4) to underset((Cathode))(2H^(+))+underset((Anode))(SO_(4)^(2-))`
`"At cathode" : " " 2H^(+)+2e^(-) to 2HorH_(2)`
`"At anode" " " 2SO_(4)^(2-) to (S_(2)O_(8))^(2-)+2e^(-)`
`(SO_(4)^(2-)` ions will take up `H^(+)` ions from the solution to from `H_(2)S_(2)O_(8)`which is peroxydisulphuric acid.