Calculate limiting molar conductivity of `CaSO_(4)` given that limiting molar conductivity of calcium and sulphate ions are 119.0 and `160.0" S "cm^(2) mol^(-1)` respectively.

Explanation

To calculate the limiting molar conductivity of \( \text{CaSO}_4 \), we will use the formula for the limiting molar conductivity of an electrolyte, which is given by the sum of the limiting molar conductivities of its constituent ions.

### Step-by-Step Solution:

1. **Identify the ions in \( \text{CaSO}_4 \)**:
- The dissociation of \( \text{CaSO}_4 \) in water can be represented as:
\[
\text{CaSO}_4 (s) \rightarrow \text{Ca}^{2+} (aq) + \text{SO}_4^{2-} (aq)
...