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Calculate equilibrium constant for the r...

Calculate equilibrium constant for the reaction :
`Mg(s) |Mg^(2+)(0.001 M) || Cu^(2+)(0.0001 M)|Cu(s)`
Given `E_((Mg^(2+)//Mg))^(@)=-2.37" V " , E_((Cu^(2+)//Cu))^(@)=0.34" V "`

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Verified by Experts

The correct Answer is:
2.68 V

Cell reaction : `Mg(s)+Cu^(2+)(0.0001"M") to Mg^(2+)(0.00" m")+Cu(s)`
`E_(cell)=E_(cell)^(@)-(0.0591)/(n)"log"([Mg^(2+)])/([Cu^(2+)])=[(0.34)-(-2.37)]-(0.0591)/(2)"log"((0.001" M"))/((0.0001M))`
`=2.71-0.02955 log10=2.68" V "`
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