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The value of DeltaG^(@) in the Daniell c...

The value of `DeltaG^(@)` in the Daniell cell has been found to be -212.3 kJ at `25^(@)C`. Calculate equilibrium constant for the reaction.

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The correct Answer is:
`1.6xx10^(37)`
`DeltaG^(@)=-2.303" RT log "K_(C) or log k_(C)=(DeltaG^(@))/(-2.303" RT")`
`DeltaG^(@)=-212.3" kJ"=-121300" J",R=8.314" J",T=298" K"`
log `K_(C)=(-212300)/(-2.303xx8.314xx298)=37.2074,K_(C)="Antilog "37.2074=1.6xx10^(37)`.
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