How much electric charge is required to produce 20.0 g of calcium from molten `CaCl_(2)` ?

Answer

96500 C

Explanation

`CaCl_(2)(l) toCa(s)+Cl_(2)(g)`
The ionic equation for the reaction is :
`underset(1" mol")(Ca^(2+))(l)+underset(2xx95600" C")(2e^(-)) to underset(1" mol"(40" g"))(Ca(s))`
To deposit 40 g of Ca (s), the number of coulombs required`=2xx96500" C"`
To deposit 20 g of Ca (s), the number of coulombs required `=2xx96500xx(20)/(40)=96500" C"`.