How many amperes would be needed to produce 60.0 g of magnesium during the electrolysis of molten `MgCl_(2)` in 2 hours ?

Answer

67 A

Explanation

`Mg^(2+)(aq)+underset(2F)underset(1mol)2e^(-) to underset(24" g.")underset(1" mol")(Mg(s))`
24.0 g of Mg are produced by passing charge `=2xx96500" C"`
60.0 g of Mg are produced by passing charge `=((60g))/((24.0g))xx(2xx96500C)=482500" C"`
`l=(Q)/(t)=((482500" C"))/((2xx60xx60s))=67.0" amp"`