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("cosh x - 1")/("sinhx") =...

`("cosh x - 1")/("sinhx")` =

A

`"sinh"x/2`

B

`"cosh " x/2`

C

`"tanh " x/2`

D

`"coth " x/2`

Text Solution

Verified by Experts

The correct Answer is:
C
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